A gallon of milk weighs eight pounds, so you wouldn’t try to carry three or four gallons home on your bicycle.  Gasoline is a bit less dense than milk—oil floats on water—and 6 pounds per gallon of gasoline is about right.  In the previous question, you looked at how many gallons of gasoline are used by a driver. A typical driver used about 600 gallons per year, with a high-use driver hitting 2000 gallons per year and a low-use driver only 200 gallons per year. Now, how much would the gasoline used by a low-use driver weigh?

Hint: The number of gallons per year, multiplied by the weight of gas as given previously, gives you the weight of gasoline burned per year:

Question

A gallon of milk weighs eight pounds, so you wouldn’t try to carry three or four gallons home on your bicycle.  Gasoline is a bit less dense than milk—oil floats on water—and 6 pounds per gallon of gasoline is about right.  In the previous question, you looked at how many gallons of gasoline are used by a driver. A typical driver used about 600 gallons per year, with a high-use driver hitting 2000 gallons per year and a low-use driver only 200 gallons per year. Now, how much would the gasoline used by a low-use driver weigh?

Hint: The number of gallons per year, multiplied by the weight of gas as given previously, gives you the weight of gasoline burned per year:

BlackTom AI · Accepted Answer

Gasoline weighs about 6 pounds per gallon, so converting gallons to weight is a simple multiplication.

1. Relevant knowledge points and concepts
- Density/weight conversion: weight = volume × weight per unit volume. Here volume is in gallons and weight per gallon is given as 6 lb/gal.
- A "low-use" driver uses 200 gallons per year (from the problem statement).

2. Complete reasoning process, step by step
- Start with the annual fuel consumption for a low-use driver: 200 gallons/year.
- Use the given weight per gallon of gasoline: 6 pounds/gallon.
- Multiply the two quantities to get annual weight burned.

3. Calculations with intermediate steps
- 200 gallons/year × 6 pounds/gallon
- First compute 2 × 6 = 12, then append the two zeros from 200 to get 1,200.
- So 200 × 6 = 1,200 pounds/year.

4. Why the correct answer is correct
- The method applies the direct conversion factor supplied in the question (6 lb per gallon) to the specified volume (200 gallons). Units cancel properly (gallons), leaving pounds per year. The arithmetic yields 1,200 pounds per year, which is the weight of gasoline burned by a low-use driver annually.

5. Why the other options are incorrect
- 120 pounds/year would correspond to only 20 gallons/year (120 ÷ 6 = 20), far below the given 200 gallons.
- 12,000 pounds/year corresponds to 2,000 gallons/year (12,000 ÷ 6 = 2,000), which matches the high-use driver, not the low-use driver.
- 120,000 pounds/year would correspond to 20,000 gallons/year (120,000 ÷ 6 = 20,000), an unrealistically large amount given the context.

6. Conclusion confirming the final answer
- Therefore, the gasoline used by a low-use driver (200 gallons/year) weighs 200 × 6 = 1,200 pounds per year. This matches the provided correct answer: 1,200 pounds / year.

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