What is printed by the following code snippet?
words = ["Today", "is", "Wednesday", "tomorrow", "is", "Thursday"]
i = 0
while i

Question

What is printed by the following code snippet?
words = ["Today", "is", "Wednesday", "tomorrow", "is", "Thursday"]
i = 0
while i < (len(words)) :
   word = words[i]
   if len(word) < 8 :
      words.pop(i)
   else :
      i = i  + 1
print(words)

BlackTom AI · Accepted Answer

We start by understanding what the code does step by step, focusing on how the list words changes and how the index i moves.
Option A: 'Nothing, this code snippet causes an IndexError: list index out of range error.' The loop uses while i < len(words) and carefully adjusts i when it pops elements. Since the code pops at index i only when the current word's length is less than 8, and i is not incremented in that branch, there isn't a direct access beyond the existing list bounds. Therefore, an IndexError does not occur in this flow.
Option B: '["Today", "is", "Wednesday", "tomorrow", "is", "Thursday"]' This would be the original list if no pops happened at all. However, the code removes items with length < 8, so the starting elements are discarded and the list shrinks as the loop progresses, making this an incorrect final state.
Option C: '["Wednesday", "tomorrow", "Thursday"]' This matches the actual evolution: starting with i = 0, 'Today' (length 5) is removed (pop), then 'is' (length 2) is removed (pop), leaving 'Wednesday' at index 0. Since 'Wednesday' has length 9, i is incremented to 1. 'tomorrow' (length 8) is kept and i becomes 2. The next element 'is' (length 2) is removed (pop) at index 2, leaving 'Wednesday', 'tomorrow', 'Thursday'. Now 'Thursday' (length 8) is kept and i increments to 3, at which point i equals len(words) and the loop ends, producing exactly '["Wednesday", "tomorrow", "Thursday"]'. This option accurately reflects the final list printed.
Option D: '["Today", "is", "is"]' This would imply the code removed a different subset of items or behaved as if the original sequence of removals led to those three elements remaining. The actual sequence of removals does not result in this trio; the remaining elements are different in both content and order compared with this option.

In summary, option C corresponds to the observable final state of the list after the loop completes, while the other options mischaracterize either the safety of the code, the original content, or the exact remaining items after all pops and index movements.

What is printed by the following code snippet? words = ["Today", "is", "Wednesday", "tomorrow", "is", "Thursday"] i = 0 while i < (len(words)) : word = words[i] if len(word) < 8 : words.pop(i) else : i = i + 1 print(words) 单项选择题

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关于列表的使用，以下哪项陈述是准确的？

列表是可变的。

A list is mutable.

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