Given the list values = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], which statement fills the list with these numbers:
1 2 3 4 5 6 7 8 9 10

Question

BlackTom AI · Accepted Answer

The problem provides an initial list: values = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], and asks which code fills the list with the sequence 1 through 10.
Option 1:
  for i in range(10) : 
     values[i] = i
This would assign 0, 1, 2, ..., 9 to values[0] through values[9], resulting in [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], not the desired 1 through 10.
Option 2 (the provided correct-looking choice):
  for i in range(10) : 
     values[i] = i + 1
This uses i from 0 to 9 and assigns i + 1 to each position, producing [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], which matches the target sequence exactly.
Option 3:
  for i in range(0, 10) : 
     values[i] = i
Here range(0, 10) yields the same values as range(10) (0 through 9), so the assignments are the same as Option 1, resulting in [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], not the intended result.
Option 4:
  for i in range(1, 10) : 
     values[i] = i
This loop iterates i from 1 to 9, leaving values[0] unchanged at 0 and setting values[1] through values[9] to 1 through 9. The final list would be [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], which again does not produce 1 through 10 and also incorrectly leaves values[0] as 0.
In summary, only Option 2 produces the exact sequence 1 through 10 in the list by adding 1 to each index value produced by the loop, while the other options either fail to increment properly or omit the first element.

Given the list values = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], which statement fills the list with these numbers: 1 2 3 4 5 6 7 8 9 10Single choice

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列表是可变的。

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