According to ABCD in 3121, the average American spent $16,803 on housing. A suburban community wants to know if their residents spent less than this national average. In a survey of 30 residents, they found that they spent an annual average of $15,800 with a standard deviation of $2,600. (  𝛼 =0.005 ) The hypothesis for this [ Select ] left-tailed two-tailed right-tailed test would be: 𝐻 0 : [ Select ] µ<15800 µ ≠115800 µ>16803 µ=16803 𝐻 𝑎 : [ Select ] µ≠15800 µ>15800 µ<16803 µ=16803 The possible decision rules for this test can be made using P-values or critical values. Using Critical Values, the null hypothesis is rejected if the test statistic is [ Select ] less greater than [ Select ] 2.33 -1.645 -1.96 -2.756 . Using P-values, the [ Select ] alternative hypthesis null hypothesis is rejected if the P-value is [ Select ] greater less than [ Select ] 0.05 0.10 0.01 0.005 . Using the [ Select ] prop.test T.Test chisq.test function in R, if we had the actual data, we would find that the point estimate of the mean amount a suburban community spend on housing is  [ Select ] $16,803 $2,600 $15,800 30 , the test statistic is [ Select ] $2,600 0.005 .0217 -2.11 $15,800 , and the P-value is [ Select ] 3121 0.02166 0.005 -2.11 . Based on this analysis, we will decide to [ Select ] reject fail to reject the [ Select ] null alternative hypothesis.  We [ Select ] have do not have evidence to suggest their residents spent less than this national average. c08.p080.q003    Multiple dropdown selections