A fitness center claims that 54% of its customers prefer being able to work out before 7 a.m.  An employee at this fitness center believes this claimed percentage is too low.  Data is subsequently gathered from a random sample of customers, and upon conducting a hypothesis test, a P-value of 0.04 is reported.  If the significance level for this hypothesis test was set at 0.05, which one of the following conclusions is most accurate?  单项选择题

A

Because 0.04 is smaller than 0.05, it has been proven that more than 54% of the fitness center customers prefer being able to work out before 7 a.m.

B

Since 0.04 is a smaller number than 0.05, this tells us the sample percentage ended up being smaller than 54%.

C

The small difference between 0.04 and 0.05 means there was only a 1% difference between the claimed population percentage and the sample percentage.

D

The resulting sample statistic is consistent with the employee’s theory that more than 54% of the fitness center customers prefer working out before 7 a.m.

E

There is strong evidence to suggest the company’s initial claim is false because 0.04 lies far below 1.

登录即可查看完整答案

我们收录了全球超50000道真实原题与详细解析,现在登录,立即获得答案。

类似问题

Historically, the mean systolic blood pressure (SBP) has been a rather high value for adults in the population. We are interested in whether a recent health campaign on diet and exercise has potentially lowered the mean. Which are the correct hypotheses?

Here are some statements relating to a P-Value When the P-Value is large (greater than 0.1) we can state the null hypothesis is true A P-Value is the probability the null hypothesis is true A P-Value is the probability of observing the test statistic, or something more extreme, if the null hypothesis is true If the P-Value is 0.06 we can reject the null hypothesis and accept the alternative hypothesis at a 10% level of significance If the P-Value is 0.04, we can reject the null hypothesis and accept the alternative hypothesis at a 1% level of significance

Sydney water claim the level of calcium carbonate in drinking water is 57mg/L, which classifies the water as soft. However, a local council are receiving an increasing number of complaints relating to excessive limescale damage of appliances and suspect their local level may be higher than that. They plan their own collection of water samples to see if the calcium carbonate levels are significantly higher than the claimed figure of 57mg/L. Let 𝜇 represent the true mean level of calcium carbonate. Here are the hypotheses the council will use: Null Hypothesis: 𝜇 = 57 Alternative Hypothesis: 𝜇 > 57 Which type of Error has been committed in the following situation? The council concludes the area's calcium carbonate level is significantly higher than 57mg/L when it is higher than the Sydney Water level of 57mg/L.  

Kettle Chips suspects that a machine which fills packets of 175g Sea Salt Chips may be wrongly calibrated and over-filling. A quality control manager takes a random sample of 100 packets and calculates the mean content to be 176g with a standard deviation of 5g. You want to find whether there is evidence that the machine is overfilling packets. What are your hypotheses?

更多留学生实用工具

加入我们,立即解锁 海量真题独家解析,让复习快人一步!