Consider the code below. What value will be displayed? int total = 0; for (int i = 1; i

Question

Consider the code below. What value will be displayed? int total = 0; for (int i = 1; i <= 4; i++) {
if (i % 2 == 0) total += i; }
MessageBox.Show(total.ToString());

BlackTom AI · Accepted Answer

To start, we examine the loop logic and what gets added to total on each iteration.
First, total is initialized to 0 before the loop begins.
Next, the loop runs with i taking values 1, 2, 3, and 4.
For each i, the condition i % 2 == 0 checks whether i is even; only even i pass this test.
When i = 1, 1 % 2 equals 1, so the condition is false and total remains 0.
When i = 2, 2 % 2 equals 0, so the condition is true and total += i adds 2 to total, making total = 2.
When i = 3, 3 % 2 equals 1, the condition is false, so total stays 2.
When i = 4, 4 % 2 equals 0, the condition is true, and total += i adds 4, resulting in total = 6.
Thus, after the loop finishes, total holds the value 6.
Now evaluating the provided options:
- a. Error: There is no syntax or runtime error in this code snippet; the loop and condition are valid in C#.
- b. 8: This would require adding both 2 and 6 or another combination that results in 8, but the loop only adds 2 and 4, yielding 6 total, not 8.
- c. 4: This would occur if only 2 was added or if the loop terminated prematurely; however, the iteration with i = 4 also contributes 4, bringing the sum to 6, not 4.
- d. 6: This matches the computed total after accumulating 2 and 4 from the even values of i.
Overall, the reasoning shows why the displayed value corresponds to the option that lists 6, given the even-number additions inside the loop.

Consider the code below. What value will be displayed? int total = 0; for (int i = 1; i <= 4; i++) { if (i % 2 == 0) total += i; } MessageBox.Show(total.ToString());Single choice

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