What is the output of the following code?

for (int x = 1; x

Question

What is the output of the following code?

for (int x = 1; x <= 10; x++) {
    x += 3;
    System.out.print(x + " ");
}

BlackTom AI · Accepted Answer

For a for-loop, the update expression (x++) runs after the loop body, so each iteration both the body’s x += 3 and the for-loop’s x++ affect x. Key concepts: for-loop execution order (initialize → check condition → body → update), compound assignment (x += 3 adds 3), and post-increment (x++ increases x by 1 after the body).

Step-by-step execution with all intermediate values:
- Initialization: x = 1.
- Iteration 1:
  - Condition: 1 <= 10 → true.
  - Body: x += 3 → x = 1 + 3 = 4.
  - Print: outputs "4 ".
  - Update (for-loop): x++ → x = 4 + 1 = 5.
- Iteration 2:
  - Condition: 5 <= 10 → true.
  - Body: x += 3 → x = 5 + 3 = 8.
  - Print: outputs "8 " (so far output "4 8 ").
  - Update: x++ → x = 8 + 1 = 9.
- Iteration 3:
  - Condition: 9 <= 10 → true.
  - Body: x += 3 → x = 9 + 3 = 12.
  - Print: outputs "12 " (so far output "4 8 12 ").
  - Update: x++ → x = 12 + 1 = 13.
- Iteration 4:
  - Condition: 13 <= 10 → false → loop terminates.

All printed values are 4, 8, 12 (each followed by a space). Thus the program prints: 4 8 12

Why other options are incorrect:
- "5 9": omits the values produced inside the body before the for-loop’s x++ and misses the third iteration value.
- "5 9 13": would be the values after the for-loop’s update if prints occurred after the update; but here printing happens inside the body before x++.
- "6 10 14": implies adding 5 each iteration or double-applying increments differently—doesn't match the actual order of x += 3 then x++.

Final confirmation: the correct output is "4 8 12", which matches the provided answer.

What is the output of the following code? for (int x = 1; x <= 10; x++) { x += 3; System.out.print(x + " "); }Single choice

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