How do you initialize a 'for' loop to count from 10 down to 1?

Question

BlackTom AI · Accepted Answer

A descending for-loop should initialize the counter at the starting value, include a condition that keeps the loop running while the counter is at or above the final value, and decrement the counter each iteration: for (int i = 10; i >= 1; i--). 1. Relevant knowledge points and concepts - A for loop has three parts: initialization, loop condition, and iteration expression. - For counting down, the iteration expression must decrement (i-- or i -= 1). - The loop condition must be true while desired values remain (i >= 1 or i > 0 for 10 down to 1). - Typical C/Java/C++ syntax: for (initialization; condition; iteration). 2. Step-by-step reasoning - Initialization: start at 10 -> int i = 10. - Condition: include i values 10 down to 1 -> i >= 1. - Iteration: move from 10 to 9 to 8 ... -> i--. 3. Intermediate steps / iteration sequence - First iteration: i = 10 (10 >= 1 is true) → body executes, then i-- makes i = 9. - Next: i = 9 (9 >= 1 true) → body, then i = 8. - ... - When i = 1: (1 >= 1 true) → body, then i-- sets i = 0. - Check: i = 0 (0 >= 1 false) → loop terminates. Values executed: 10,9,8,7,6,5,4,3,2,1. 4. Why the correct answer is correct - for (int i = 10; i >= 1; i--) exactly matches initialization (10), correct stopping condition (>= 1), and decrementing iteration (i--) to traverse 10 down to 1 inclusive. 5. Why other options are incorrect - for (int i = 0; i < 10; i--): starts at 0 and decrements (i--), so i becomes negative and the condition i < 10 remains true forever → infinite loop and wrong range. - for (int i = 10; i >= 1; i++): starts at 10 but increments (i++), so i grows and i >= 1 stays true → infinite loop, wrong direction. - for (int i = 10; i >= 0; i++): starts at 10 and increments; condition i >= 0 stays true forever → infinite loop, and it does not count down to 1. 6. Conclusion The correct loop is for (int i = 10; i >= 1; i--), which matches the provided answer.

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