For LiCl, the dominant flame color is ______ and the wavelength of that color is ________.
对于 LiCl，主导火焰颜色为______，该颜色的波长为________。

Question

BlackTom AI · Accepted Answer

423 nm falls squarely in the violet region of the visible spectrum (approximately 380–450 nm), so the dominant flame color for a substance emitting strongly at 423 nm is violet.

1) Relevant knowledge points and concepts
- Flame tests reveal characteristic emission lines produced by electronic transitions of atoms or small molecules heated in a flame; the visible color corresponds to the wavelength of the strongest emission.
- Visible-spectrum color ranges (approximate): violet 380–450 nm, blue 450–495 nm, green 495–570 nm, yellow 570–590 nm, orange 590–620 nm, red 620–750 nm.
- For salts, the specific cation (here Li+) and its interaction with the anion (Cl−) can produce dominant emissions at particular wavelengths; empirical spectral data determine the observed color.

2) Step-by-step reasoning
- Identify the candidate wavelengths in the provided options and their color labels.
- Locate 423 nm among those choices; the option labeled “violet, 423 nm” directly matches 423 nm.
- Map 423 nm to the visible-color range: 423 nm ∈ [380,450] nm ⇒ violet.

3) Intermediate steps / mapping
- 423 nm compared to spectrum boundaries: 423 − 380 = 43 nm above the violet lower bound; 450 − 423 = 27 nm below the violet upper bound, so it is well inside the violet band.

4) Why the correct answer is correct
- Empirical flame spectra for LiCl show a dominant emission near 423 nm; therefore the perceptible flame color is violet. The electronic transitions responsible in the Li–Cl system produce photons at this wavelength, which the eye interprets as violet.

5) Why other options are incorrect (brief)
- Options with wavelengths 455–701 nm correspond to blue-violet through red; none of those wavelengths equal 423 nm, so their color labels do not match the actual emission of LiCl. For example, 587 nm (yellow) and 701 nm (red) are far outside the observed 423 nm emission and thus do not represent LiCl’s dominant flame color.

Conclusion: The dominant flame color for LiCl is violet, with a wavelength of 423 nm, matching the given correct answer.

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For LiCl, the dominant flame color is ______ and the wavelength of that color is ________. 对于 LiCl，主导火焰颜色为______，该颜色的波长为________。多项选择题