Question textGuidelines to answer the following question:Fill in the blanks with the correct answers. Do NOT use any spaces or brackets. For all numerical answers, give EXACT values (i.e. do not round your answers) unless instructed otherwise in the question. If using fractions, give answers as SIMPLIFIED fractions using the forward slash (e.g. 1/2 or 5/4). Use - for any negatives. _____________________________________________________________This question is worth 1 + 1 + 1 + 1 + 1 + 2 + 1 = 8 marks. The mass, [math: M] grams of a radioactive material, Radon-222, at time [math: t] seconds after start of the experiment can be modelled by the equation: [math: M=70e−0.002t].a) Find the initial amount of Radon-222. Answer: [math: M=] Answer 1 Question 6[input] grams. [1 mark]b) Find the amount of Radon-222 present 60 seconds after the start of the experiment. Round your answer to the nearest gram. Answer: [math: M=] Answer 2 Question 6[input] grams. [1 mark]c) How long after the start of the experiment will the mass be decayed to 20 grams? Round your answer to the nearest second. Answer: It will take Answer 3 Question 6[input] seconds. [1 mark] Another radioactive material Cobalt-60 has a half life of 6 years. This means that in 6 years, a given amount (mass) of the radioactive material will decay to half of its original amount.Initially a scientist has 100 grams of Cobalt-60 in his laboratory at the beginning of an experiment.The mass, [math: M] grams of Cobalt-60 at time [math: t] years after start of the experiment can be modelled by the equation: [math: M=Moe−kt], where [math: t≥0], and [math: k] is a positive constant.d) Find the value of [math: Mo].[math: Mo=] Answer 4 Question 6[input]. [1 mark]e) What is the amount (mass) of the radioactive material after 6 years? Answer: [math: M=]Answer 5 Question 6[input] grams. [1 mark]f) Find the exact value of [math: k] in the form of [math: 1alogeb], where [math: a]nd [math: b] are positive integers. Hence give the values of [math: a]nd [math: b]elow: [math: a=] Answer 6 Question 6[input] [math: b=] Answer 7 Question 6[input] [2 marks]g) Write the value of [math: k] correct to 3 decimal places. [math: k=] Answer 8 Question 6[input] [1 mark]多项填空题

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Question at position 16 Initially, three are 50 milligrams of a radioactive substance. The substance decays according to the equation N = 50e-0.01t, where N is the number of milligrams present after t hours. The number of hours it takes for 10 milligrams to remain is−ln⁡(0.01)5-\frac{\ln\left(0.01\right)}{5}50e−0.150e^{-0.1}−ln⁡(15)0.01-\frac{\ln\left(\frac{1}{5}\right)}{0.01}−15ln⁡(−0.01)-\frac{\frac{1}{5}}{\ln\left(-0.01\right)}−15ln⁡(0.01)-\frac{\frac{1}{5}}{\ln\left(0.01\right)}

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