5. Which of the following function headers is correct?
A. def f(a = 1, b):
B. def f(a = 1, b, c = 2):
C. def f(a = 1, b = 1, c = 2):
D. def f(a = 1, b = 1, c = 2, d):

Question

BlackTom AI · Accepted Answer

When evaluating Python function headers, the key rule is that once a parameter has a default value, all subsequent parameters must also have default values. This prevents a non-default parameter from following a default one in the function signature.
Option A: "def f(a = 1, b):" Here, parameter a has a default value, but parameter b does not. This breaks the rule because a non-default parameter (b) follows a default parameter (a). Therefore, this is invalid.
Option B: "def f(a = 1, b, c = 2):" In this header, b is a non-default parameter that appears after a parameter with a default value (a = 1). This is not allowed in Python function definitions, so this is invalid.
Option C: "def f(a = 1, b = 1, c = 2):" All parameters have default values, and there is no parameter without a default after a default. This adheres to the rule, so this header is valid.
Option D: "def f(a = 1, b = 1, c = 2, d):" Here, d is a non-default parameter that comes after several parameters with default values. Since a non-default parameter follows defaults, this is invalid for the same reason as option A and B.
Thus, the valid function header among the choices is the one where every parameter has a default value without violating the default-after-non-default rule, and that is the header shown in option C.

5. Which of the following function headers is correct? A. def f(a = 1, b): B. def f(a = 1, b, c = 2): C. def f(a = 1, b = 1, c = 2): D. def f(a = 1, b = 1, c = 2, d): Single choice

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