Hypochlorite Application APF is used in the debridement of ulcers and infected wounds. It has the following formula: Calcium Hypochloride Solution 45 mLCetamacrogol Emulsifying Wax 10 gLiquid Paraffin 45 gCalcium Hypochloride Solution contains 0.3% w/v of available Chlorine.The density of Calcium Hypochlorite Solution is 1.00 g/mL How much available Chlorine is there per gram of Hypochlorite Application APF?单项选择题
A
a. 0.0135 g
B
b. 13.5 g
C
c. 0.00135 g
D
d. 1.35 g
E
e. 0.135 g

Question

Hypochlorite Application APF is used in the debridement of ulcers and infected wounds. It has the following formula: Calcium Hypochloride Solution 45 mLCetamacrogol Emulsifying Wax 10 gLiquid Paraffin 45 gCalcium Hypochloride Solution contains 0.3% w/v of available Chlorine.The density of Calcium Hypochlorite Solution is 1.00 g/mL How much available Chlorine is there per gram of Hypochlorite Application APF?单项选择题

A

a. 0.0135 g

B

b. 13.5 g

C

c. 0.00135 g

D

d. 1.35 g

E

e. 0.135 g

BlackTom AI · Accepted Answer

0.3% w/v means 0.3 g of available chlorine per 100 mL of the calcium hypochlorite solution.

1) Relevant concepts
- “% w/v” means grams solute per 100 mL solution.
- Density converts solution volume to mass when needed (here density = 1.00 g/mL so 1 mL = 1 g).
- Total mass of the final formulation is the sum of the masses of all components; available chlorine per gram = total chlorine mass ÷ total product mass.

2) Step-by-step calculation
- Volume of hypochlorite solution used = 45 mL.
- Available chlorine concentration = 0.3 g per 100 mL.
- Mass of available chlorine in 45 mL = (0.3 g / 100 mL) × 45 mL
  = 0.3 × 0.45 g
  = 0.135 g.
- Convert solution volume to mass (for total product mass): density = 1.00 g/mL so 45 mL = 45 g.
- Masses of other components: cetamacrogol wax = 10 g; liquid paraffin = 45 g.
- Total mass of final product = 45 g (solution) + 10 g + 45 g = 100 g.
- Available chlorine per gram of product = total chlorine mass / total product mass
  = 0.135 g ÷ 100 g
  = 0.00135 g available chlorine per gram.

3) Why this answer is correct
The 0.00135 g/g result follows directly from converting the % w/v to grams in the actual volume used, summing product mass correctly, and dividing. No extra conversions are necessary because density = 1 g/mL simplifies volume-to-mass.

4) Why the other options are incorrect
- a (0.0135 g) is ten times too large (likely a decimal-place error).
- b (13.5 g) and d (1.35 g) are orders of magnitude too large (misplacing the percent or forgetting the “per 100 mL” factor).
- e (0.135 g) is the total chlorine in the 45 mL solution, not the amount per gram of final product.

Conclusion: The correct amount of available chlorine per gram of Hypochlorite Application APF is 0.00135 g, matching option c.

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