Question textGuidelines to answer the following question:Fill in the blanks with the correct answers. Do NOT use any spaces or brackets. For all numerical answers, give EXACT values (i.e. do not round your answers) unless instructed otherwise in the question. If using fractions, give answers as SIMPLIFIED fractions using the forward slash (e.g. 1/2 or 5/4). Use - for any negatives. _____________________________________________________________This question is worth 1 + 2 + 2 + 2 = 7 marks.The amount of liquid [math: V m3] in a medium-sized pool at time [math: t] days is given by [math: V=50(t+1)2] for [math: 0≤t≤6].a) The initial volume of liquid in the pool is Answer 1 Question 8[input] [math: m3]. [1 mark]b) The derivative of [math: V] with respect to [math: t] can be written in the form [math: dVdt=A(t+1)B]where [math: A,B∈R].State the value of [math: A] and [math: B]:[math: A=] Answer 2 Question 8[input] [math: B=] Answer 3 Question 8[input] [2 marks]c) The rate of change of volume is [math: −4 m3/day] when the time [math: t=] Answer 4 Question 8[input] days (correct to 3 decimal places). At this time, the volume of liquid in the pool is [math: V=] Answer 5 Question 8[input] [math: m3] (correct to 3 decimal places). [2 marks]d) From the graph of [math: dVdt] (drawn using a calculator), it can be seen that [math: dVdt] is Answer 6 Question 8[select: , negative, positive, zero] for [math: 0≤t≤6], so the volume of liquid in the pool is Answer 7 Question 8[select: , decreasing, increasing, neither] .  [2 marks]Multiple fill-in-the-blank