The following application was developed to allow a user to guess a number between 0 and 10. If a number between 0 and 10 is entered, the number is not accepted.How can this error be removed?

Question

BlackTom AI · Accepted Answer

The repeat-until loop stops when its condition becomes true, so the condition must describe a valid input to stop repeating. 1. Relevant knowledge points and concepts - repeat until : the body repeats while is false and stops when becomes true. - Logical operators: OR (true if either operand true), AND (true only if both true), and NOT (negation). - De Morgan’s law: not (A or B) is equivalent to (not A) and (not B). 2. Step-by-step reasoning - Current condition in the screenshot: repeat until (number < 0) OR (number > 10). - Evaluate what happens for different inputs: - If number is between 0 and 10 (valid): number < 0 is false, number > 10 is false, so (false OR false) = false. repeat until false means the loop continues (i.e., it keeps asking), so a valid number is not accepted. - If number is outside 0–10 (invalid): at least one of number < 0 or number > 10 is true, so the OR is true, and repeat until true stops immediately — an invalid number becomes accepted. - This is the reverse of the intended behavior. To stop repeating when the input is valid, the loop’s condition must be true for valid numbers. 3. Intermediate logical steps / transformation - Desired stopping condition: number is between 0 and 10 inclusive → (number >= 0) AND (number <= 10). - Using the original terms, that is the negation of the invalid check: not (number < 0 OR number > 10). - By De Morgan: not (A or B) = (not A) and (not B), so not (number < 0 or number > 10) = (number >= 0) and (number <= 10). 4. Why the correct answer is correct - Changing the condition to not (number < 0 or number > 10) makes the condition true exactly when the number is valid, so the loop stops for valid input and continues for invalid input — fixing the bug. 5. Why other options are incorrect - b. Deleting the say block only removes the message; it does not fix the reversed loop condition. - c. Changing to number < 0 AND number > 10 is always false (a number cannot be both less than 0 and greater than 10), so the loop would never stop. - d. Using repeat instead of repeat until would create an infinite loop unless another break mechanism exists; it does not correct the logical test. 6. Conclusion - The correct fix is option a: change the condition to not (number < 0 or number > 10), which matches the provided answer.

The following application was developed to allow a user to guess a number between 0 and 10. If a number between 0 and 10 is entered, the number is not accepted.How can this error be removed?单项选择题

类似问题

Question at position 3 What will the following code output? a = (True and (not False or (True and False))) b = not (False and (not True or (True and False))) c = True and (not (True and (False or True))) print(a, b, c)True True FalseFalse True FalseTrue False FalseFalse True TrueClear my selection

Question at position 1 The achieve a pass in INFO1110 you must:(Pass the Foundation Test) AND (Pass the Foundation Assignment)(Pass the Foundation Test)(Pass the Foundation Test) OR (Pass the Foundation Assignment)(Pass the Foundation Assignment)Clear my selection

The content of A1 is hidden from you. But, you know that a logical value was entered in that cell. When you execute the following formula in A3, what would be the outcome returned in A3? =OR(A1=TRUE,A1=FALSE)

After completing the following formula, suppose you type it in an empty cell and execute it successfully. The result returned in that cell is c. =IF([Fill in the blank] ,IF(FALSE,"a","b"),"c") Complete the formula above with a value. Only logical value is allowed. No function name is allowed.

Given that a = True and b = False, what would the following expression evaluate to? a and not b or not a

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单