Consider the following code: int[] Arr = { 77, 10, 124, 63, 22}; int x = Arr[4]; for (int index=3; index = 0; index--) { if (Arr[index]

Question

Consider the following code: int[] Arr = { 77, 10, 124, 63, 22}; int x = Arr[4]; for (int index=3; index >= 0; index--) {
if (Arr[index] < x) {
x =
Arr[index]; }
} MessageBox.Show(x.ToString()); What will be the output displayed on Message Box?

BlackTom AI · Accepted Answer

To begin reasoning through this code, let's restate the setup: we have an array int[] Arr = { 77, 10, 124, 63, 22 }; and x is initialized to Arr[4], which equals 22. The loop for (int index = 3; index >= 0; index--) iterates over indices 3, 2, 1, and 0 in that order, comparing Arr[index] to x and updating x when Arr[index] is smaller.

Option A: 10
This option corresponds to a scenario where one of the earlier elements is smaller than the initial x and gets assigned to x. In the loop, when index reaches 1, Arr[1] is 10, which is less than the current x (22). Therefore, x becomes 10, and no later element (77 at index 0, 63 at index 3, and 124 at index 2) is smaller than 10 to update x again. So 10 is possible and ends up being the final value.

Option B: 63
This would require x to be updated to 63 at some point, but 63 is not less than the initial 22, so the condition Arr[index] < x is false for index = 3. Since 63 is greater than 22, the code never assigns x = 63.

Option C: 77
77 is the first element of the array, but the only way x would become 77 is if Arr[index] < x evaluated to true with x currently greater than 77 at some iteration. Since x starts at 22 and all remaining elements are either larger than 22 or equal only at 22 itself, there is no update to 77. Thus x cannot become 77.

Option D: 22
While 22 is the initial value of x, the loop checks for strictly smaller elements (Arr[index] < x). If a smaller element exists later, x would be updated. Here, 10 is smaller than 22 and appears in the array, so x becomes 10 and cannot revert back to 22. Therefore 22 cannot be the final value.

In summary, the loop finds the smallest value encountered after the initial x by updating x only when a smaller element is found. The sequence of checks leads to x becoming 10 when Arr[1] = 10 is found to be less than 22, after which no smaller element is encountered. Consequently, the output shown in the MessageBox will be 10.

Consider the following code: int[] Arr = { 77, 10, 124, 63, 22}; int x = Arr[4]; for (int index=3; index >= 0; index--) { if (Arr[index] < x) { x = Arr[index]; } } MessageBox.Show(x.ToString()); What will be the output displayed on Message Box?单项选择题

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