[table]
Individual | CSF1PO | D3S1358 | D5S818 | D7S820 | D8S1179 DNA Evidence | 5,6 | 3,3 | 10,15 | 16,19 | 3,5 2 | 10,10 | 6,7 | 12,12 | 14,14 | 7,7 3 | 7,8 | 3,4 | 12,14 | 19,20 | 3,5 4 | 7,7 | 5,5 | 11,12 | 14,17 | 4,5 5 | 5,5 | 4,4 | 10,11 | 15,16 | 4,4 6 | 11,13 | 3,8 | 13,14 | 17,17 | 4,4 7 | 12,13 | 7,8 | 14,14 | 18,19 | 6,9 8 | 13,13 | 5,5 | 10,14 | 19,20 | 5,5 9 | 7,9 | 5,5 | 11,12 | 14,20 | 4,5 10 | 10,11 | 3,6 | 10,11 | 15,15 | 4,4 11 | 11,13 | 3,8 | 13,14 | 17,19 | 4,4 12 | 12,12 | 6,7 | 14,14 | 18,20 | 6,9 13 | 6,6 | 5,5 | 10,14 | 14,15 | 5,5 14 | 5,12 | 4,7 | 14,14 | 18,19 | 6,9 15 | 11,13 | 5,5 | 10,15 | 20,20 | 5,5
[/table] Calculate the probability of Allele 5 for CSF1PO. P(5) = Answer Question 14[input] Round your answer accurately to the 3rd decimal place. Hint: Recall that the probability of a given allele is the same as calculating the frequency of that allele in the sample, which is individuals 2-15 in this section.

Question

BlackTom AI · Accepted Answer

First, I restate the task in my own words to ensure clarity: we need to compute the frequency of allele 5 for CSF1PO using the sample of individuals 2 through 15, treating each individual’s two alleles as separate observations.

Next, I extract the CSF1PO allele data from individuals 2 to 15 from the table:
- 2: 10, 10
- 3: 7, 8
- 4: 7, 7
- 5: 5, 5
- 6: 11, 13
- 7: 12, 13
- 8: 13, 13
- 9: 7, 9
- 10: 10, 11
- 11: 11, 13
- 12: 12, 12
- 13: 6, 6
- 14: 5, 12
- 15: 11, 13

Then I count how many of these 28 alleles are equal to 5. Individual 5 contributes two 5 alleles (5,5), giving 2 occurrences. Individual 14 contributes one 5 allele (5,12), giving 1 more occurrence. All other individuals in this range have no allele 5.

So total occurrences of allele 5 across the 28 alleles (14 individuals × 2 alleles each) = 2 + 1 = 3.

The allele frequency is the number of times allele 5 appears divided by the total number of alleles examined: 3/28.

Compute the decimal: 3 ÷ 28 = 0.107142857...

Round to three decimal places as requested: 0.107.

Summary of reasoning path: identify the correct subset of individuals (2–15), tally each occurrence of allele 5 across both alleles per individual, divide by total allele count (28), and round the result to three decimals. This matches the provided answer of 0.107. If you want to cross-check, recounting the 28 alleles and highlighting the two alleles from individual 5 and the single 5 from individual 14 confirms the same total of 3 occurrences.

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