The oxidation of a secondary alcohol with acidified dichromate will produce

Question

BlackTom AI · Accepted Answer

When examining what happens to a secondary alcohol under oxidation with acidified dichromate, we should consider the oxidation products typical for primary versus secondary alcohols. 
Option a: a carboxylic acid. This would be the product if a primary alcohol were oxidized all the way to a carboxylic acid, but secondary alcohols do not proceed to carboxylic acids under this reagent; therefore this option is incorrect for secondary alcohol oxidation. 
Option b: an aldehyde. An aldehyde would be the product of oxidizing a primary alcohol (stopping at the aldehyde stage), or in some cases a secondary alcohol could briefly form a ketone that further oxidizes under harsh conditions, but with standard acidified dichromate, the secondary alcohol does not yield an aldehyde. So this choice misrepresents the typical outcome for secondary alcohols. 
Option c: a ketone. This is the textbook product of oxidizing a secondary alcohol with acidified dichromate: the hydroxyl-bearing carbon loses two hydrogens to form a carbonyl, yielding a ketone. This aligns with the general oxidation pattern of secondary alcohols. 
Option d: a saturated organic compound. “Saturated” refers to lack of double bonds; oxidation of an alcohol does not produce a generic saturated hydrocarbon, and this option fails to specify the oxidation product type. It’s not a correct description of the process or product here. 
In summary, the oxidation of a secondary alcohol with acidified dichromate yields a ketone, not a carboxylic acid, aldehyde, or a nonspecific saturated compound, making option c the accurate choice.

The oxidation of a secondary alcohol with acidified dichromate will produceSingle choice

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