Given that a function with a single stationary point has:Single choice

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Question textGuidelines to answer the following question:Fill in the blanks with the correct answers. Do NOT use any spaces or brackets. For all numerical answers, give EXACT values (i.e. do not round your answers) unless instructed otherwise in the question. If using fractions, give answers as SIMPLIFIED fractions using the forward slash (e.g. 1/2 or 5/4). Use - for any negatives. _____________________________________________________________This question is worth 2 + 2 + 1 = 5 marks.The graph of [math: f(x)=x3+ax2+bx+2] has a stationary point at [math: (3,−7)]. a) Use the given information to set up two simultaneous equations. Fill in the blanks. Answer 1 Question 7[input] [math: a+b=−12] (1) Answer 2 Question 7[input] [math: a+b=−27] (2) [2 marks] b) Solve the equations to find the values of [math: a]nd [math: b]. [math: a=] Answer 3 Question 7[input] [math: b=] Answer 4 Question 7[input] [2 marks]c) State the nature of the stationary point at [math: (3,−7)]. Select the correct answer : Answer 5 Question 7[select: , local minimum, local maximum, stationary point of inflection]. [1 mark]

The stationary point for \( y=(2+x)e^{-x} \) is:

If the function [math: f(x)=x3+4x2+4x] f(x)=x^3+4x^2+4x has a stationary point at (-2,0), the other stationary point is:

Question textGuidelines to answer the following question:Fill in the blanks with the correct answers. Do NOT use any spaces or brackets. For all numerical answers, give EXACT values (i.e. do not round your answers) unless instructed otherwise in the question. If using fractions, give answers as SIMPLIFIED fractions using the forward slash (e.g. 1/2 or 5/4). Use - for any negatives. _____________________________________________________________This question is worth 2 + 2 = 4 marks.The graph of [math: g(x)=ax3+bx2+16] g(x)=ax^3+bx^2+16 has both an x-intercept and a turning point at [math: x=2] . a. Use the given information to set up two simultaneous equations. Fill in the blanks.Answer 1 Question 5[input][math: a+b=−4] a+ b=-4 (1)Answer 2 Question 5[input][math: a+b=0] a+ b=0 (2) b. Solve the equations to find the values of [math: a] and [math: b] .[math: a=] Answer 3 Question 5[input] [math: b=] Answer 4 Question 5[input]

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