Question at position 19 Which of the following values would NOT cause this program to exit with an error? values = ####dict = {"a": 45, "b": "Pass", "c": True, "d": -5}for key in values: print(f"{key} has value {dict[key]}")values = ["0", "1", "3" ]values = [45, "Pass", -5] values = ["a", "b", "d"] values = [0, 1, 3]Clear my selectionSingle choice
A
values = ["0", "1", "3" ]
B
values = [45, "Pass", -5]
C
values = ["a", "b", "d"]
D
values = [0, 1, 3]

Question

Question at position 19 Which of the following values would NOT cause this program to exit with an error? values = ####dict = {"a": 45, "b": "Pass", "c": True, "d": -5}for key in values: print(f"{key} has value {dict[key]}")values = ["0", "1", "3" ]values = [45, "Pass", -5] values = ["a", "b", "d"] values = [0, 1, 3]Clear my selectionSingle choice

A

values = ["0", "1", "3" ]

B

values = [45, "Pass", -5]

C

values = ["a", "b", "d"]

D

values = [0, 1, 3]

BlackTom AI · Accepted Answer

Dictionary lookup requires that the loop variable exactly match an existing key. Here the dictionary (named dict) maps the string keys "a", "b", "c", "d" to values 45, "Pass", True, and -5. The for loop iterates over whatever list is assigned to values and then tries to access dict[key]. If key is not one of the dictionary’s keys (or is a different type), dict[key] raises a KeyError (or TypeError if an unhashable type), causing the program to exit with an error.

Step-by-step reasoning:
1. The dictionary contents:
   - dict["a"] -> 45
   - dict["b"] -> "Pass"
   - dict["c"] -> True
   - dict["d"] -> -5
2. The loop does: for key in values: print(f"{key} has value {dict[key]}")
   - For each element of values, Python will use that element as the dictionary key lookup.
3. Evaluate each answer option:
   - values = ["0", "1", "3"]: The strings "0","1","3" are not keys in dict. First iteration tries dict["0"] → KeyError. Error occurs.
   - values = [45, "Pass", -5]: These are dictionary values, not keys. Attempting dict[45] fails because 45 is not a key (the key "a" maps to 45, but 45 is not a key). KeyError occurs on first lookup.
   - values = ["a", "b", "d"]: All three are valid keys present in dict. Lookups:
       dict["a"] → 45 (prints "a has value 45")
       dict["b"] → "Pass" (prints "b has value Pass")
       dict["d"] → -5 (prints "d has value -5")
     No error occurs.
   - values = [0, 1, 3]: Integers 0,1,3 are not keys (keys are strings), so dict[0] raises KeyError.

Why the correct answer is correct:
Only the list ["a","b","d"] supplies keys that exist in the dictionary, so each lookup succeeds and no exception is raised.

Conclusion: The value that would NOT cause the program to exit with an error is values = ["a", "b", "d"], which matches the provided answer.

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