The figure presents a parallel connection of two identical resistors. The equivalent overall resistance of the circuit is

Question

BlackTom AI · Accepted Answer

First, let's identify the configuration shown: two resistors of equal value appear connected in parallel between the same two terminals. When resistors are in parallel, the reciprocal of the total resistance is the sum of the reciprocals of each individual resistance. Here, each resistor is 10 Ohms.

So, 1/R_eq = 1/10 + 1/10 = 2/10 = 1/5. Therefore, R_eq = 5 Ohms.

Now evaluate the options:
- Option a: 20 Ohms. This would be the total resistance if the resistors were in series (R_eq = R1 + R2 = 10 + 10 = 20). Since the configuration is parallel, this value does not apply.
- Option b: 100 Ohms. This is much larger than any single resistor and does not correspond to any standard simple combination of two 10-Ohm resistors; it would require an open circuit or a misinterpretation of labeling.
- Option c: 5 Ohms. This matches the parallel-combination result for two equal 10-Ohm resistors, where the combined resistance is half of a single one.
- Option d: 10 Ohms. This would be the resistance of a single resistor; having two in parallel reduces the total resistance, not keep it the same.

Thus, by applying the parallel-resistor rule and comparing with each option, you can see how the various values arise from different arrangements (series vs parallel) and why they are or aren’t appropriate for this circuit.

The figure presents a parallel connection of two identical resistors. The equivalent overall resistance of the circuit isSingle choice

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