Predict the organic product(s) of the following reaction. Choose all products that will form.

Question

BlackTom AI · Accepted Answer

Ionization to a carbocation (SN1) is the key step: heating a secondary alkyl chloride in a weakly nucleophilic, neutral alcohol (iPrOH) favors loss of Cl– to give a planar carbocation intermediate, which is then trapped by the alcohol to form an alkyl ether (the isopropyl ether). Because the carbocation is sp2 planar, nucleophilic attack can occur from either face, giving both stereochemical outcomes at that carbon.

1) Relevant concepts
- SN1 mechanism: rate-determining ionization to carbocation, followed by nucleophilic capture.
- Planar carbocation leads to racemization (attack from both faces) at the reacting center.
- A stereocenter not involved in cation formation remains unchanged (no inversion at remote centers).
- iPrOH is the nucleophile, so the product is the corresponding isopropyl ether (alkoxy substitution), not substitution by a stronger nucleophile.

2) Step-by-step reasoning
- The C–Cl bond breaks under heat to give a carbocation at that stereocenter.
- The carbocation is planar, so nucleophilic attack by iPrOH can occur from the front or back face.
- Attack from each face produces two stereoisomeric ethers that differ only in the configuration at the former stereocenter.
- No strong base is present to force a concerted SN2 or exclusively promote E2; elimination (E1) could be a minor pathway, but the major pathway under these conditions with solvent nucleophile is SN1 substitution.

3) Intermediate steps (conceptual)
- R–CH(Cl)– → R–C+–H (planar) + Cl–
- R–C+–H + iPrOH → R–C(OR')–H (attack from either face) + H+

4) Why the correct answers are correct
- The first and fourth product images show the isopropyl ether with the two possible configurations at the substituted carbon; these correspond to nucleophilic attack from opposite faces of the planar carbocation and therefore are both formed.

5) Why other options are incorrect
- Any option showing only one stereochemical outcome at the reacting center would be inconsistent with SN1 racemization.
- Structures that change a different stereocenter, show substitution at a different carbon, or depict an impossible migration are not produced under simple SN1 trapping with iPrOH.
- Options that depict an unrelated alkyl group (e.g., ethoxy instead of isopropoxy) or rearranged skeleton are also incorrect.

Conclusion: Both stereochemical isomers formed by nucleophilic attack on the planar carbocation are produced, so the first and fourth options are correct, matching the provided answer.

Predict the organic product(s) of the following reaction. Choose all products that will form. Multiple choice

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