What is the ending value of y?

int x;
int y; x = 2;
y = ((x + 1) / 5) + (x / 2) ;

Question

What is the ending value of y?

int x; 
int y; x = 2; 
y = ((x + 1) / 5) + (x / 2) ;

BlackTom AI · Accepted Answer

Integer division truncates the fractional part, so all / operations between ints produce integer results. Also, parentheses control evaluation order but here simply group the two divisional subexpressions which are then added.

1) Relevant knowledge points and concepts
- Variables x and y are declared as int, so arithmetic between them uses integer arithmetic.
- Integer division discards any fractional part (in C/C++/Java it truncates toward zero for positive numbers this is equivalent to floor).
- Operator precedence: parentheses force evaluation of (x + 1) / 5 and x / 2 before the addition.

2) Complete step-by-step reasoning
- Start with the assignments: x = 2.
- Compute the first subexpression: (x + 1) / 5.
  - x + 1 = 2 + 1 = 3.
  - 3 / 5 using integer division = 0 (since 3/5 = 0.6 and the fractional part is discarded).
- Compute the second subexpression: x / 2.
  - x = 2, so 2 / 2 = 1 (integer division gives exact 1).
- Add the two integer results: 0 + 1 = 1.

3) Intermediate calculation summary
- x + 1 = 3
- (x + 1) / 5 = 3 / 5 = 0 (integer)
- x / 2 = 2 / 2 = 1
- y = 0 + 1 = 1

4) Why the correct answer is correct
Because both divisions involve int operands, fractional results are truncated. The (x+1)/5 term yields 0, so the only contribution is x/2 = 1, giving y = 1.

5) Why the other options are incorrect
- 4.5: No sequence of integer operations here yields 4.5; this would require a different expression or wrong arithmetic.
- 1.6: This is the floating-point result (0.6 + 1.0) if divisions were done in floating point. But with int types, fractional part is discarded.
- Error: Division not possible: not applicable because denominators (5 and 2) are nonzero; no runtime or compile-time division error occurs.

6) Conclusion
The final value of y is 1, which matches the provided correct answer: 1.

What is the ending value of y? int x; int y; x = 2; y = ((x + 1) / 5) + (x / 2) ;Single choice

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