Question at position 19 Consider the following code snippet: class LinearEquation: def __init__(self, m, b): self.m = m # slope self.b = b # y-intercept # Missing code: define a method that, given x, returns y = mx + b. Which option correctly fills in the missing code?def solve(self, x): return self.m * x + self.bdef solve(self, x): print(self.m * x + self.b)def solve(self, x): return self.m + x + self.bdef solve(m, b, x): return m * x + bClear my selection单项选择题
A
def solve(self, x): return self.m * x + self.b
B
def solve(self, x): print(self.m * x + self.b)
C
def solve(self, x): return self.m + x + self.b
D
def solve(m, b, x): return m * x + b

Question

Question at position 19 Consider the following code snippet: class LinearEquation: def init(self, m, b): self.m = m # slope self.b = b # y-intercept # Missing code: define a method that, given x, returns y = mx + b. Which option correctly fills in the missing code?def solve(self, x): return self.m * x + self.bdef solve(self, x): print(self.m * x + self.b)def solve(self, x): return self.m + x + self.bdef solve(m, b, x): return m * x + bClear my selection单项选择题

A

def solve(self, x): return self.m * x + self.b

B

def solve(self, x): print(self.m * x + self.b)

C

def solve(self, x): return self.m + x + self.b

D

def solve(m, b, x): return m * x + b

BlackTom AI · Accepted Answer

Question at position 19 asks about completing a class method that computes y = mx + b for a given x. The class stores m as the slope and b as the y-intercept in __init__. The missing code should define a method solve(self, x) that returns the value of mx + b.

Option 1:
def solve(self, x):
    return self.m * x + self.b
This option defines a method solve that takes x as input and returns self.m * x + self.b, which matches the intended formula y = mx + b. It uses the instance attributes m and b correctly and returns the numeric result without printing it, which is appropriate for a function that computes and returns a value.

Option 2:
def solve(self, x):
    print(self.m * x + self.b)
This version computes the value but prints it instead of returning it. If the goal is to provide a reusable value to other parts of the program, returning the value is necessary; printing would be a side effect and would prevent further programmatic use of the result.

Option 3:
def solve(self, x):
    return self.m + x + self.b
This implementation miscomputes the formula by summing m, x, and b, rather than multiplying m by x. It would produce incorrect results for y = mx + b unless m or x are zero in a trivial case.

Option 4:
def solve(m, b, x):
    return m * x + b
This function signature omits the self parameter, making it a standalone function rather than a method of LinearEquation. It would work if called with explicit m, b, and x values, but it does not operate as a bound method on an instance, so it would not access the instance attributes m and b automatically.

In summary, among the given choices, the first option correctly implements a method that computes y = mx + b using the instance's attributes and returns the result, while the other options either alter the behavior (printing instead of returning), compute an incorrect expression, or change the method to a non-bound function.