In the AVR assembly language, what value is stored in the data location 0x101 after the following lines of code?

.section .data
.byte 31, 10, 16, 2, 138, 5, 9

Question

In the AVR assembly language, what value is stored in the data location 0x101 after the following lines of code?

.section .data
.byte 31, 10, 16, 2, 138, 5, 9

BlackTom AI · Accepted Answer

The .byte directive stores its listed values consecutively in memory, so the byte at address 0x101 is the second value in the list, 10.

1) Relevant knowledge points and concepts
- The .data section and .byte directive: .byte v1, v2, ... places each v as one consecutive byte in data memory.
- Addresses increment by 1 per byte (no multi-byte packing or endianness issues for single bytes).
- If the first byte is at address 0x100, the nth byte is at address 0x100 + (n − 1).

2) Step-by-step reasoning
- The assembler will store the bytes in the order given: 31, 10, 16, 2, 138, 5, 9.
- Assign addresses sequentially starting from the base address under consideration. The question asks specifically about address 0x101, so treat the first listed byte as being at 0x100 and increment accordingly.

3) Intermediate steps / explicit mapping (with hex conversions)
- 31 decimal = 0x1F → stored at 0x100
- 10 decimal = 0x0A → stored at 0x101
- 16 decimal = 0x10 → stored at 0x102
- 2 decimal = 0x02  → stored at 0x103
- 138 decimal = 0x8A → stored at 0x104
- 5 decimal = 0x05  → stored at 0x105
- 9 decimal = 0x09  → stored at 0x106

4) Why the correct answer is correct
Because each .byte entry occupies exactly one byte and they are placed in sequence, the entry at address 0x101 is the second entry in the list. The second listed value is 10 (0x0A), so 10 is stored at 0x101.

5) Why other possible values would be incorrect
- 31 would be incorrect because that is the first byte (at 0x100), not 0x101.
- 16, 2, 138, 5, 9 are at subsequent addresses (0x102–0x106), not 0x101.
- No endianness or multi-byte alignment changes this result because all entries are single bytes.

6) Conclusion
Therefore the value stored at data location 0x101 is 10, which matches the provided answer.

In the AVR assembly language, what value is stored in the data location 0x101 after the following lines of code? .section .data .byte 31, 10, 16, 2, 138, 5, 9Short answer

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